Mohon bantuannya!!! (No. 9 dan 10)

nomer 10
T1 = y = x
T2 = matriks
T2 o T1
[tex] \binom{1 \: \: \: \: 2}{0 \: \: \: \: 1} \times \binom{0 \: \: \: \: 1}{1 \: \: \: \: 0} = \binom{2 \: \: \: \: \: 1}{1 \: \: \: \: \: 0} [/tex]
[tex] \binom{ {x} }{y} = \frac{1}{ - 1} \binom{0 \: \: \: \: \: - 1}{ - 1 \: \: \: \: \: \: \: \: \: 2} \binom{ {x}^{l} }{ {y}^{l} } \\ \binom{x}{y} = - 1 \binom{ { - y}^{l} }{ { - x}^{l} + {2y}^{l} } \\ \binom{x}{y} = \binom{ {y}^{l} }{ {x}^{l} - {2y}^{l} } [/tex]
x = y'
y = x'- 2y'

maka persamaan garis bayangannya
2x + y + 4 = 0
2(y') + (x' - 2y') + 4 = 0
2y' + x' - 2y' + 4 = 0
x + 4 = 0
E