Matematika

Pertanyaan

tentukan himpunan selesaian dari persamaan-persamaan dibawah ini! a.
[tex]4(x - 4) = 20[/tex]
b.
[tex] \frac{y + 4}{2} = 25[/tex]
[tex]c.2p = - 12 - \frac{2}{5} p[/tex]
[tex]d. \frac{4p - 2}{5} + \frac{p + 2}{4} = 21[/tex]
tolong dijawab dengan cara nya

terima kasih

1 Jawaban

  • a.
    [tex]4(x - 4 )= 20 \\ 4x - 16 = 20 \\ x = \frac{20 + 16}{4} = \frac{36}{4} = 12[/tex]
    b.
    [tex] \frac{y + 4}{2} = 25 \\ y + 4 = 25(2) \\ y = 50 - 4 = 46[/tex]

    c.
    [tex]2p = - 12 - \frac{2}{5} p \\ 2p + \frac{2}{5} p = - 12 \\ \frac{10}{5} p + \frac{2}{5} p = - 12 \\ \frac{12}{5} p = - 12 \\ p = - 12( \frac{5}{12} ) = - 5[/tex]
    d.
    [tex] \frac{4p - 2}{5} + \frac{p + 2}{4} = 21 \\ \frac{4(4p - 2)}{20} + \frac{5(p + 2)}{20} = 21 \\ \frac{16p - 8}{20} + \frac{5p + 10}{20} = 21 \\ \frac{16p + 5p - 8 + 10}{20} = 21 \\ \frac{21p + 2}{20} = 21 \\ \frac{21p}{20} + \frac{2}{20} = 21 \\ \frac{21p}{20} + \frac{1}{10} = 21 \\ \frac{21p}{20} = 210 \\ p = 210( \frac{20}{21} ) = 200[/tex]

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