Matematika

Pertanyaan

4x(pangkat2)-3x+12<3x(pangkat2)+4x+2

2 Jawaban

  • x^2 - 7x + 10
    (x - 2 ) ( x - 5 )
    x= 2  ;  x= 5
  • 4x^2 - 3x + 12 < 3x^2 + 4x + 2
    4x^2 - 3x^2 - 3x - 4x + 12 - 2 < 0
    x^2 - 7x + 10 < 0
    (x-5)(x-2) < 0
    ¤x-5 < 0
    x < 5
    ¤ x-2 < 0
    x < 2

    ~ x^2 - 7x + 10 < 0
    (3)^2 - 7(3) + 10 < 0
    9 - 21 + 10 < 0
    ~ x^2 - 7x + 10 < 0
    (1)^2 - 7 (1) + 10 < 0
    1 - 7 + 10 < 0
    4 < 0
    ~ x^2 - 7x + 10 < 0
    (6)^2 - 7 (6) + 10 < 0
    36 - 42 + 10 < 0
    4 < 0

    hp = {x|2<x<5}

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