tolong jawab no 14 dan 15 pakai caranya

nomer 14
[tex]
\frac{1}{(x + 3)} + \frac{4}{(2x + 6)} = \\ \frac{1(2x + 6) + 4(x + 3)}{(x + 3)(2x + 6)} = \\ \frac{2x + 6 + 4x + 12}{(x + 3)(2x + 6)} = \\ \frac{(6x + 18)}{(x + 3)(2x + 6)} \\ \frac{6(x + 3)}{(x + 3)(2x + 6)} \\ \frac{6}{2x + 6} \\ \frac{3}{x + 3}
[/tex]

nomer 15
[tex] \frac{ \frac{x}{y} - \frac{y}{x} }{ \frac{2y}{x} - \frac{2x}{y} } \\ \frac{\frac{ {x}^{2} - {y}^{2} }{xy} }{ \frac{ {2y}^{2} - {2x}^{2} }{xy} } \\ \frac{ {x}^{2} - {y}^{2} }{xy} \times \frac{xy}{ {2y}^{2} - {2x}^{2} } \\ \frac{ {x}^{2} - {y}^{2} }{2 {y}^{2} - 2 {x}^{2} } \\ \frac{ 1({x}^{2} - {y}^{2}) }{ - 2( - {y}^{2} + {x}^{2} ) } \\ - \frac{1}{2} [/tex]