No 12 ya pake cara makasii

11. 2x+7  = 5x-11
      2x-5x = -11-7
      -3x      = -18
      x        = [tex] \frac{-18}{-3} [/tex]
      x        = 6
ditanya x+3
           = 6+3
           = 9 (B.)
12.  [tex] \frac{1}{4} x + 5= \frac{1}{2}(2x-5) [/tex]
       [tex] (\frac{1}{4} x + 5= \frac{1}{2}(2x-5))4 [/tex]
       dikali 4 agar pecahan hilang
      = 1(x+5)=2(2x-5)
      =1x+5   =4x-10
      =x-4x   = -10-5
      =-3x      =-15
      =x         = [tex] \frac{-15}{-3} [/tex]
      =x         = 5
13.  3x-5  > x+3    
      =3x-x >3+5
      =2x    >8
      =x      >[tex] \frac{8}{2} [/tex]
      =x      > 4