Matematika

Pertanyaan

tentukan rumus fungsi (-4, -2), (-2, -1), (2, 1), (4, 2)

1 Jawaban

  • (-4,-2)
    [tex](x - ( - 4))(x - ( - 2)) \\ (x + 4)(x + 2) \\ x ^{2} + 6x + 8[/tex]



    (-2,-1)
    [tex](x - ( - 2))(x - ( - 1)) \\ (x + 2)(x + 1) \\ x^{2} + 3x + 2[/tex]


    (2, 1)
    [tex](x + 2)(x + 1) \\ x^{2} + 3x + 2[/tex]


    (4, 2)
    [tex](x + 4)(x + 2) \\ x ^{2} + 6x + 8[/tex]

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