tentukan persamaan garis yg melalui titikA. (3,4) dan bergradien 3/4

y-y1=m(x-x1)
y-4=3/4(x-3)
y-4=3/4x-9/4
__________ x4
4y-16=3x-9
4y-3x-16+9=0
4y-3x-7=0 atau 4y-3x=7

y-y1 = m(x-x1)
y-4 = 3/4(x-3)
4(y-4) = 4[3/4(x-3)]
4y-16 = 3(x-3)
4y-16 = 3x-9
4y = 3x+16-9
4y = 3x+7
4y-3x = 7
4y-3x-7 = 0