1/6 ( 3x +1) + 1/3 (x-2) = 1 1/6 Tolong bantu jawabannya sama caranya ya...

1 / 6 (3x+1) + 1 / 3 (x-2) = 11 / 6
= 1 / 2 x + 1 / 6 + 1 / 3 x - 2 / 3 = 11 / 6
= (1 / 2 x + 1 / 3 x) + (1 / 6 - 2 / 3) = 11 / 6
= 3 + 2 / 6 x + 1 - 4 / 6 = 11 / 6
= 5 / 6 x + (-3 / 6) = 11 / 6
= 5 / 6 x = 11 / 6 + 3 / 6
= x = 14 / 6 × 6 / 5
      = 14 / 5
      = 2[tex] \frac{4}{5}[/tex]