3log 27 - 2log 20 - 2log 2/5+ 5log 625=
Matematika
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Pertanyaan
3log 27 - 2log 20 - 2log 2/5+ 5log 625=
1 Jawaban
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1. Jawaban algebralover
³log 27 = ³log 3³ = 3 × ³log 3 = 3 × 1 = 3
²log 20 = ²log (4 × 5) = ²log 2² + ²log 5 = (2 × ²log 2) + ²log 5 = 2 + ²log 5
²log (²/₅) = ²log 2 - ²log 5 = 1 - ²log 5
⁵log 625 = ⁵log 5⁴ = 4 × ⁵log 5 = 4 × 1 = 4
= ³log 27 - ²log 20 - ²log (²/₅) + ⁵log 625
= (3) - (2 + ²log 5) - (1 - ²log 5) + (4)
= 3 - 2 - ²log 5 - 1 + ²log 5 + 4
= (3 - 2 - 1 + 4) + (²log 5 - ²log 5)
= 4 + 0
= 4