Penyelesaian nilai mutlak |6-x|=|2x+3|

Positif :
|6 - x | = |2x + 3|
6 - x = 2x + 3
6 - 3 = 2x + x
3 = 3
x = 3/3
x = 1

Negatif :
-(6 - x) = 2x + 3
-6 + x = 2x + 3
-6 - 3 = 2x - x
-9 = x
x = 9

|6-x| = |2x+3|
Jawab :
6-x = 2x+3
6-3 = 2x+x
3 = 3x
X = 1
Atau
-(6-x) = 2x+3
-6+x = 2x+3
-6-3 = 2x-x
-9 = x

Hp = {–9, 1}