Matematika

Pertanyaan

2log16+2log32
2log8-2log1/4

2 Jawaban

  • 2log16+2log32
    = 2log2^4 + 2log2^5
    = 4+5
    = 9

    2log8-2log1/4
    = 2log8/1/4
    = 2log32
    = 2log2^5
    = 5
  • ²log16 + ²log32
    ²log2⁴ + ²log2*5 (maksudnya 2 pangkat 5 ya)
    4²log2 + 5²log2
    4 + 5 = 9

    ²log8 - ²log¼
    ²log2³ - ²log4-² (maksudnya 4 pangkat -2 ya)
    3²log2 - (-2)²log2
    3 + 2 = 5

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