Matematika

Pertanyaan

mohon di jawab ya kak soalnya besok dikumpul
mohon di jawab ya kak soalnya besok dikumpul

1 Jawaban

  • 1) ( 3x - 4y )( 9x² + 12xy + 8y² )
    = 27x³ - 36x²y + 36x²y - 48xy² + 24xy² - 32y³
    = 27x³ - 24xy² - 32y³

    2) x² + 7x
    -------------------
    x² + 3x - 28

    = x ( x + 7 )
    ----------------------
    ( x - 4)( x + 7 )

    = x
    -----------
    x - 4

    3) f(x) = 3x + 2
    a) f(5) = 3(5) + 2 = 15 + 2 = 17
    b) f(a) = 3a + 2
    38 = 3a + 2
    38 - 2 = 3a
    36 = 3a
    a = 36 ÷ 3
    a = 12

    4) a) g(x) = px + q
    g(3) = 3p + q = - 4
    g(-2) = - 2p + q = 1
    ---------------------------(-)
    5p = - 5
    p = - 1
    subtitusi
    3p + q = - 4
    3p - 1 = - 4
    3p = - 4 + 1
    3p = - 3
    p = - 1
    b) g(x) = px + q
    g(x) = - x - 1
    c) g(-5) = - (-5) - 1 = 5 - 1 = 4

    5) m = ( y2 - y1 ) / ( x2 - x1 )
    m = ( 4 + 2 ) / ( - 2 - 5 )
    m = 6 / - 7
    m = - 6/7

    6) a) 3x + 2y - 6 = 0
    2y = - 3x + 6
    m = -3/2
    gradien sejajar
    m1 = m2 = - 3/2
    pers garis
    y - y1 = m ( x - x1 )
    y + 4 = - 3/2 ( x - 8 )
    y = - 3/2 x + 12 - 4
    y = - 3/2 x + 8 ( dikali 2)
    2y = - 3x + 16
    2y + 3x = 16
    b) 2x - 4y + 8 = 0
    - 4y = - 2x - 8
    m = - 2/-4
    m = ½
    gradien tegak lurus
    m1 . m2 = - 1
    ½ . m2 = - 1
    m2 = -1 ÷ ½
    m2 = - 2
    Pers garis
    y - y1 = m ( x - x1 )
    y + 4 = - 2 ( x - 8)
    y = - 2x + 16 - 4
    y + 2x = 12

    7) 2x + y = 4
    2x - 3y = 12
    -------------------(-)
    4y = - 8
    y = - 2
    subtitusi
    2x + y = 4
    2x - 2 = 4
    2x = 4 + 2
    2x = 6
    x = 3
    nilai 4x - y
    = 4(3) - (-2)
    = 12 + 2
    = 14

    8) misal
    bilangan 1 = x
    bilangan 2 = y
    x + y = 35
    x - y = 5
    ---------------(-)
    2y = 30
    y = 15
    subtitusi
    x - y = 5
    x - 15 = 5
    x = 5 + 15
    x = 20
    nilai x • y
    = 20 • 15
    = 300

    9) ½d1 = ½ × 12 = 6 cm
    ½d2 = ½ × 16 = 8 cm
    sisi miring = √(½d1² + ½d2²)
    = √(6² + 8²)
    = √(36 + 64)
    = √100
    = 10 cm
    K = 4 × sisi miring
    = 4 × 10
    = 40 cm

    10) c = √a² + b²
    c = √(4)² + (5)²
    c = √16 + 25
    c = √41
    c tdk sm sg 6 berarti segitiga sembarang

    c = √(6)² + (8)²
    c = √36 + 64
    c = √100
    c = 10
    c sama² 10 cm, berarti segitiga siku²

    c = √(6² + 8²)
    c = √(36 + 64)
    c = √100
    c = 10
    c tdk sama dg 10, berarti segitiga sembarang