0 < ×< 1\2 dan×|2×-1| +|×|(×-2)<2×

x |2x-1| + |x| (x-2) < 2x , u.s 0<x<1/2
=> x [-(2x-1)] + (x)[-(x-2)] < 2x
=> x (1-2x) + x(2-x) < 2x
=> x-2x^2 + 2x-x^2 - 2x < 0
=> -3x^2 + x < 0
=> x(1 - 3x) < 0
=> x=0 v x=1/3

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- 0 + 1/3 -

x<0 atau x>1/3