tolong pakai cara.....

[tex] \frac{2x}{4 } - \frac{x + 4}{6} \geqslant \frac{2}{3} [/tex]
[tex] \frac{6x}{12} - \frac{2x + 8}{12} \geqslant \frac{2}{3} [/tex]
[tex] \frac{6x - 2x + 8}{12} \geqslant \frac{2}{3} [/tex]
[tex] \frac{4x + 8}{12} \geqslant \frac{2}{3} [/tex]
[tex]3(4x + 8) \geqslant 24[/tex]
[tex]12x + 28 \geqslant 24[/tex]
[tex]12x \geqslant 24 - 28[/tex]
12x≥-4
x≥-4:12
x≥-1:3
x≥-⅓

hp:{x|x≥-⅓, x€bil rasional}

Jawabannya;
2x/4-x+4/6≥2/3
= 6x/12-2x+8/12≥2/3
= 6x-2x+8/12≥2/3
= 4x+8/12 ≥ 2/3
= 3(4x+8)≥24
= 12x+28≥24
= 12x≥24-28
= 12x≥-4
= x≥-4/12
= x≥-1/3

HP={ x | x > -1/3, x € bil. rasional }

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