1)tentukan persamaan garis melalui titik (-3,2) sejajar 2x-y+2=0 2)tentukan persamaan garis melalui titik (2,-5) tegsk lurus y=3x+5

1. m=-a/b = -2/-1 = 2
    y-y1 = m (x-x1)
    y-2 = 2 (x-(-3))
    y-2 = 2 (x+3)
    y-2 = 2x + 6
    y= 2x + 6 + 2
    y= 2x + 8

2. m = -a/b = -3/1 = 1/3
    y-y1 = m (x-x1)
    y-(-5) = 1/3 (x-2)
    y+5 = 1/3 x - 2/3
    _____________·3
   3y+15 = 1x -2
   3y = 1x -2 - 15
   3y = 1x -17


pointnya ya...