pers garis yg melalu titik (-6, -8) dan tegak lurus dgn garis yg persamaan nya 2x + 5y + 10 = 0 adalah

m1 = -a/b
m1 = -2/5
m1 × m2 = -1
-2/5 × m2 = -1
m2 = -1/-2/5
m2 = -1 × -5/2
m2 = 5/2
y - y1 = m(x - x1)
y - (-8) = 5/2(x - (-6))
y + 8 = 5/2(x + 6)
2(y + 8) = 5(x + 6)
2y + 16 = 5x + 30
2y - 5x = 30 - 16
2y - 5x = 14