Tentukanlah hasil pergeseran garis 2y-3x+6=0 ditranslasikan oleh T(4,-1)

Cara 1
A + T = A'
A' = (x, y) + (4, -1)
A' = (x + 4, y - 1)
X' = x + 4 »» x = x' - 4
Y' = y - 1. »» y = y' + 1

Maka persamaan bayangan garisnya
2y - 3x + 6 = 0
2(x' - 4) - 3(y' + 1) + 6 = 0
2x' - 8 - 3y' - 3 + 6 = 0
2x - 3y - 5 = 0

Cara 2
T(4, -1)
2x - 3y = -6 + 2(4) - 3(-1)
2x - 3y = -6 + 8 + 3
2x - 3y = 5
2x - 3y - 5 = 0