hasil dari garis singgung x^2+y^2+4x-6y-7=0 dititi yang barabsis 2

PGSL

x² + y² + 4x - 6y - 7 = 0
(x + 2)² + (y - 3)² = 7 + 2² + 3²
(x + 2)² + (y - 3)² = 20
2(x + 2)dx + 2(y - 3)dy = 0
dy/dx = m = -(x + 2)/(y - 3)

absis = x = 2
(2 + 2)² + (y - 3)² = 20
4² + (y - 3)² = 20
(y - 3)² = 4
y - 3 = 2 atau y - 3 = -2
y = 5 atau y = 1

PGSL 1
titik singgung = (2,5)
m = -(x + 2)/(y - 3) = -(2 + 2)/(5 - 3)
m = -2
pgsl :
y - y1 = m(x - x1)
y - 5 = -2(x - 2)
y = -2x + 9

PGSL 2
titik singgung = (2,1)
m = -(2 + 2)/(1 - 3) = 2
pgsl :
y - 1 = 2(x - 2)
y = 2x - 3