Tentukan penyelesaian dari SPLDV berikut dengan metode eliminasi a.x+4y=10 2x+5y=12 b.2x+4y=2 3x-2y=-8 c.2x+3y=-4 3x-2y=-19

a) x + 4y = 10 |×2
2x + 5y = 12
maka
2x + 8y = 20
2x + 5y = 12
-------------------(-)
3y = 8
y = 8/3
• x + 4y = 10 |×5
2x + 5y = 12 |×4
maka
5x + 20y = 50
8x + 20y = 48
---------------------(-)
3x = 2
x = ⅔
hp = ( ⅔ , 8/3 )

b) 2x + 4y = 2
3x - 2y = - 8 |×2
maka
2x + 4y = 2
6x - 4y = - 16
-------------------(+)
8x = - 14
x = - 14/8
x = - 7/4
• 2x + 4y = 2 |×3
3x - 2y = - 8 |×2
maka
6x + 12y = 6
6x - 4y = - 16
-------------------(-)
16y = 22
y = 22/16
y = 11/8
hp = ( - 7/4 , 11/8 )

c) 2x + 3y = - 4 |×2
3x - 2y = - 19 |×3
maka
4x + 6y = - 8
9x - 6y = - 57
-------------------(+)
13x = - 65
x = - 5
• 2x + 3y = - 4 |×3
3x - 2y = - 19 |×2
maka
6x + 9y = - 12
6x - 4y = - 38
--------------------(-)
13y = 26
y = 2
hp = ( -5,2 )