2 buah hambatan dirangkai pararel 4 ohm dan 2 ohm di hubungkan dengansumber arus 12 Volt hitung kuat arus dan Beda potensial masing masing hambaran

Hambatan (R) =

[tex] \frac{1}{4} + \frac{1}{2} = \frac{1}{4} + \frac{2}{4} = \frac{3}{4} = \frac{4}{3} \: ohm[/tex]

Kuat Arus Rangkaian (I) = V/R
= 12 ÷ 4/3
[tex] = 12 \times \frac{3}{4} [/tex]
→ 9 Ampere

rangkaian paralel: I beda, V sama

Kuat Arus setiap hambatan:
4 ohm → 12 ÷ 4 = 3 Ampere
2 ohm → 12 ÷ 2 = 6 Ampere

Beda Potensial (V):
4 ohm → 12 V
2 ohm → 12 V

1/Rp = 1/R1+1/R2
= 1/4 + 1/2
= 4/3ohm
I = V/R
= 12/4/3
= 12 x 3/4
= 9A
I1 = V/R1
= 12/4
= 3A
I2 = V/R2
= 12/2
= 6A
Beds potential hambatan 1&2 itu 12V
Karna tegangan di tiap titik pararel itu sama